How 4 mole of hcl equals 1 mole of mno2
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Equation for the reaction: MnO2(s)+4HCl(aq) —> Cl2(g)+MnCl2(aq)+H2O(l)
Using stoichiometry, we know that for every 1 mol of MnO2(s), 4 moles of HCl (aq) will react with it. So if we have 4.56 moles of MnO2, 4*4.56 moles of HCl (aq) will react.
18.2 moles HCl.(aq)
MnO2 +4 H+ + 2e- = Mn2+ +2 H2O
2 Cl- = Cl2 + 2e-
MnO2 + 4 HCl = Cl2 + MnCl2 + 2 H2O
the ratio between MnO2 and HCl is 1 : 4
moles HCl required = 4 x 4.56 /1 = 18.24 moles of HCl
Hope Its HelpFul....
Using stoichiometry, we know that for every 1 mol of MnO2(s), 4 moles of HCl (aq) will react with it. So if we have 4.56 moles of MnO2, 4*4.56 moles of HCl (aq) will react.
18.2 moles HCl.(aq)
MnO2 +4 H+ + 2e- = Mn2+ +2 H2O
2 Cl- = Cl2 + 2e-
MnO2 + 4 HCl = Cl2 + MnCl2 + 2 H2O
the ratio between MnO2 and HCl is 1 : 4
moles HCl required = 4 x 4.56 /1 = 18.24 moles of HCl
Hope Its HelpFul....
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