Physics, asked by Priyam2368, 1 year ago

How acceleration due to gravity vto gravity varies with depth

Answers

Answered by ccbhedke
2
Force is inversely proportional to the radius of Earth [distance (s)]. We know that, Earth is not a correct sphere. It is flatten at its pole and wider at equator. Therefore, the acceleration due to gravity (g) is varying when depth is increased or decreased. Its the principle by Issac Newton. He states that, gravitational force (F) is directly proportional to the product of masses of the objects (Mm) and inversely proportional to the square of the radius or distance (d^2 / r ^2).

F = GMm / d^2

Where G is universal gravitational constant. Its value is 6.673 × 10^-11.
Answered by ChromaticSoul
7

As depth increases, the value of acceleration due to gravity (g) falls. The value of g is more at equator and less at poles.

Formula: g = GM/r2

Values of g in CGS: 980 cm s-2

Values of g in SI: 9.806 ms-2

Dimensional Formula: M0L1T-2

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