Math, asked by radhika4venugopal, 5 days ago

how am i supposed to do the 6th sum tell me pls

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Answered by kinzal
4

Here is your answer ❤️⏬

  \sf \frac{ {5}^{4}  \times  {3}^{4}  \times 4}{9 \times  {5}^{3} \times 2 }  \\

we can write 9 as = 3²

and also 4 as = 2²

So,

  \sf   \frac{5^{4} \times  {3}^{4} \times  {2}^{2}  }{ {3}^{2} \times  {5}^{3}  \times 2 } \\

   \sf  ( {5}^{4}  \times  {3}^{4}  \times  {2}^{2}) \times (3 ^{ - 2}  \times  {5}^{ - 3}  \times  {2}^{ - 1} ) \\

 \sf  {5}^{4 - 3}  \times  {3}^{4 - 2}  \times  {2}^{2 - 1}  \\

  \sf  {5}^{1}  \times  {3}^{2}  \times  {2}^{1}  \\

 \sf 5 \times 9 \times 2 \\

 \sf \underline{ \boxed{ \mathfrak{90}}} \\

I hope it helps you ❤️✔️

Answered by crystal200
4

Step-by-step explanation:

HOPE THIS WILL HELP YOU ^^

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