How ammonia will be formed when 7g of nitrogen react with hydrogen
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The stoichiometric equation is:
3H2 + N2 → 2NH3
According to the stoichiometric equation, 6g of H2 combines with 28g of N2.
So, 1.09g of H2 will combine with = (1.09 × 28)/6 = 5.0866g of N2.
Now, 14 of N2 is used, according to the question.
So, H2 is the limiting reagent and N2 is the excess reagent.
Now, according to the stoichiometric equation, 6g of H2 produces 34g of NH3.
So, 1.09g of H2 will produce = (1.09 × 34)/6 = 6.176g of NH3
3H2 + N2 → 2NH3
According to the stoichiometric equation, 6g of H2 combines with 28g of N2.
So, 1.09g of H2 will combine with = (1.09 × 28)/6 = 5.0866g of N2.
Now, 14 of N2 is used, according to the question.
So, H2 is the limiting reagent and N2 is the excess reagent.
Now, according to the stoichiometric equation, 6g of H2 produces 34g of NH3.
So, 1.09g of H2 will produce = (1.09 × 34)/6 = 6.176g of NH3
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