how any number of moles of O2 gas are required to burn 10 dm ³ of C2H4
Answers
Answered by
0
C2H4 + 3O2 =====> 2CO2 + 2H2O
1 mole of C2H4 = 3 mole of O2
10 dm = 10 L
10 L = 10/22.4 = 0.45 mole
No of O2 mole = 0.45×3 = 1.35 mole
1 mole of C2H4 = 3 mole of O2
10 dm = 10 L
10 L = 10/22.4 = 0.45 mole
No of O2 mole = 0.45×3 = 1.35 mole
Similar questions