Question

How are ethylamine and ethyl methyl amine distinguished by using nitrous acid?

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Answer 1

Explanation:

Ethylamine (a primary amine) reacts with nitrous acid in cold condition to give ethyl alcohol with liberation of nitrogen gas.

CH

3

−CH

2

−NH

2

+HNO

2

NaNO

2

+HCl

273−278 K

CH

3

−CH

2

−OH+H

2

O+N

2

↑

Ethyl methyl amine (a secondary amine) reacts with nitrous acid in cold condition to give yellow oily N-nitrosoethyl methyl amine.

CH

3

−CH

2

−NH−CH

3

+HNO

2

NaNO

2

+HCl

273−278 K

CH

3

−CH

2

−N(CH

3

)−N=O+H

2

O

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