Question

how are K.E. and momentum related​

Answer 1

Answer :

→K.E = (P.E)²/2M

$K.E = \frac{1}{2} M {(V)}^{2}$

$P.E = MV \\ → {(P.E)}^{2} = {(MV) }^{2} \\ → {(P.E)}^{2} = {M}^{2} {V}^{2} \\→ \frac{1}{2} {(P.E)}^{2} = M.\frac{1}{2} M {V}^{2} \\ → \frac{1}{2} {(P.E)}^{2} = M.(K.E) \\ →K.E = \frac{{(P.E)}^{2}}{2M}$