Question

How are primary , secondary and tertiary alcohols prepared from grignard reagent? write the reaction​

Answer 1

The Grignard reaction is the only simple method available that is capable of producing primary, secondary, and tertiary alcohols.

Explanation:

1) Primary Alcohol is formed when Grignard's reagent is added to HCHO it means formaldehyde.

2) To produce a primary alcohol, the Grignard reagent is reacted with formaldehyde.                          H

                                                  |       HCl

$CH_{3} MgBr$    +   H-C=O------>$CH_{3} -CH_{2} -OH  +  Mg(Br)Cl$

Here methyl magnesium bromide it is also known as girgnard reagent with formaldehyde we will get ethanol. It is called as primary alcohol reaction.

3) Reacting a Grignard reagent with any other aldehyde will lead to a secondary alcohol.     O                                                       OH

                                     ||                                                        |

$CH_{3} MgBr  +  CH_{3} -CH$------> $CH_{3} -CH-CH_{3}$  + Mg(Br)Cl

In this reaction methyl magnesium bromide reacts with acetaldehyde we will get 2-propanol and it is known as secondary alcohol.

4) Finally, reacting a Grignard reagent with a ketone will generate a tertiary alcohol.                                                    O                                                CH3

                                                                 ||                                                 ||

$CH_{3} MgBr$   +  $CH_{3} -C-CH_{3}$----->$CH_{3}-C-CH_{3}  +Mg(Br)Cl$

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