How are (semi-) static fields treated quantum-mechanically?
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The Schwinger pair production can be understood as follows:
Suppose you have a constant electric field E in some region of space, pointing in the x direction. This is created for example by a large capacitor. Inside this capacitor, the energy of an electron-positron pair separated by some distance ΔxΔx is V(Δx)=2m−qEΔxV(Δx)=2m−qEΔx, where mm is the mass of the electron (and positron) and qq is its charge. The first term is the rest energy of two massive particles, and the second is their potential energy in the presence of the electric field. You can see that for large enough separation the total energy is negative - it becomes energetically favourable to have a pair present instead of an empty capacitor.
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PLZZZ MARK AS BRAINLIEST ANSWER
The Schwinger pair production can be understood as follows:
Suppose you have a constant electric field E in some region of space, pointing in the x direction. This is created for example by a large capacitor. Inside this capacitor, the energy of an electron-positron pair separated by some distance ΔxΔx is V(Δx)=2m−qEΔxV(Δx)=2m−qEΔx, where mm is the mass of the electron (and positron) and qq is its charge. The first term is the rest energy of two massive particles, and the second is their potential energy in the presence of the electric field. You can see that for large enough separation the total energy is negative - it becomes energetically favourable to have a pair present instead of an empty capacitor.
HOPE THIS WAS HELPFUL
PLZZZ MARK AS BRAINLIEST ANSWER
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Hey !
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Semi static quantum mechanics told us that we should not believe on what we see.
Else we should find out the meaning of the seen thing.
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Thanks !
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