How are the following salts prepared ?
(a) Urea
(b) Copper sulphate
(c) Alum
Answers
Answer:
a) Urea is byproduct of converting alkyl halides to thiols via a S-alkylation of thiourea. Such reactions proceed via the intermediacy of isothiouronium salts: RX + CS(NH2)2 → RSCX(NH2)2X. In this reaction R is alkyl group, X is halogen and M is an alkali metal.
Chemical formula: CH4N2O
Solubility: 500 g/L glycerol 50g/L ethanol; ~4 g/L acetonitrile
Solubility in water: 1079 g/L (20 °C); 1670 g/L (40 °C); 2510 g/L (60 °C); 4000 g/L (80 ...
Melting point: 133 to 135 °C (271 to 275 °F; 406 to 408 K)
b) copper sulphate (soluble salt) from an insoluble base (copper oxide) and sulphuric acid? 1. Pour 25 cm3 of sulfuric acid into a beaker. ... Heat the beaker and stir until reaction is complete.
c) Alum, any of a group of hydrated double salts, usually consisting of aluminum sulfate, water of hydration, and the sulfate of another element.Weigh 12.5g of potassium sulfate and dissolved in a minimum quantity of distilled water in a beaker. Stir to dissolve the crystals. Take a conical flask, in that dissolve 50g of aluminium sulfate in warm water and add 3ml of dilute sulphuric acid to make the solution clear. Filter the solutions if it is not clear.
Explanation:
i hope it's helpful
Answer:
copper sulphat
Explanation:
salt are prepare by reacting onl acid metal or base such metal carbonate hydroex or oxide...