Question

how are the two alpha angles equal​

Answer 1

Explanation:

Given expression, sin

2

α+sin

2

β+sin

2

γ

=(1−cos

2

α)+(1−cos

2

β)+(1−cos

2

γ)

=3−cos

2

α+cos

2

β+cos

2

γ=3−1=2

(∵cos

2

α+cos

2

β+cos

2

γ=1)