How are two resistors with resistances R1Ω and R2Ω are to be connected to a battery of emf 3 volts to obtain maximum current flowing through it ?
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Answer:
we all know by ohms law that
v=ir
3=ir
i=3/r
for i to be maximum r needs to be minimum
the resistance in a parallel circuit is smaller than the resistance in a series circuit.
hence a parrallel connection is required
Explanation:
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