Question

How are you all good morning solve it.
$( \frac{2}{3}) ^{3} \times ( \frac{2}{3} ) ^{6} = ( \frac{4}{9} ) ^{2k - 3} \ \textless \ br /\ \textgreater \ ​$
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Answer 1

$\bf \bigg( \frac{2}{3} \bigg) ^{3} \times \bigg( \frac{2}{3} \bigg) ^{6} = \bigg( \frac{4}{9} \bigg) ^{2k - 3} \\ \\ \bf \bigg( \frac{2}{3} \bigg) ^{(3 + 6)} = \bigg( \frac{2}{3} \bigg) ^{2(2k - 3)} \\ \\ \pmb{3 + 6 = 2(2k - 3)} \\ \\ \pmb{9 = 4k - 6} \\ \\ \pmb{4k = 15} \\ \\ \blue{ \boxed{\pmb{k = \frac{15}{4} }}}$

Answer 2

$\large \green{ \fcolorbox{gray}{black}{ ☑ \: \textbf{Verified \: answer}}}$

$\huge \mathbb{\pmb{k = \frac{15}{4} }}$