How calculate conduction period of diode rectifier?
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How can we calculate the conduction period of the diode when a half-wave rectifier is used to charge a 12 Volts Battery through a resistance 'R'? Given the input is fed by 34 Volts AC with turns ratio 2:1
My Approach:
we know for half-wave rectifier:
ω×Δt=√((2×Vr)/Vp)ω×Δt=√((2×Vr)/Vp)
GivenVpm=34V,Vo=12VandTurnratio=2:1GivenVpm=34V,Vo=12VandTurnratio=2:1
⟹Vsm=17V⟹Vsm=17V
Also we know:
Vo=Vsm−(Vr/2)Vo=Vsm−(Vr/2)
⟹12=17−(Vr/2)⟹12=17−(Vr/2)
⟹Vr=10V⟹Vr=10V
∴ω×Δt=1.08inrador62.14o∴ω×Δt=1.08inrador62.14o
but answer is given as 120 degree
My Approach:
we know for half-wave rectifier:
ω×Δt=√((2×Vr)/Vp)ω×Δt=√((2×Vr)/Vp)
GivenVpm=34V,Vo=12VandTurnratio=2:1GivenVpm=34V,Vo=12VandTurnratio=2:1
⟹Vsm=17V⟹Vsm=17V
Also we know:
Vo=Vsm−(Vr/2)Vo=Vsm−(Vr/2)
⟹12=17−(Vr/2)⟹12=17−(Vr/2)
⟹Vr=10V⟹Vr=10V
∴ω×Δt=1.08inrador62.14o∴ω×Δt=1.08inrador62.14o
but answer is given as 120 degree
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