how can 3 resistors of resistance 3ohm so that the combination has a resistance of 1ohm and 2ohm
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if you put all of them in parallel, you get 1 ohm
put two of them in series and the third one as parallel to both of them, you'll get 2 ohm
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1 ohm
1/3+1/3+1/3= 3/3= 1 ohm.
hence verified.
for 2 ohm
2 in series and one parallel to it.
3+3= 6 ohm(series).
6 ohm and 3 ohm parallel.
1/6+1/3 = 3/6= 1/2
equivalent resistance = 2 ohm.
hence verified.
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