how can 3 resistors of resistances 1ohm ,3ohm and 5ohm be connected to give a total resistance of 2ohm
Answers
Answer:
1 ohm and 5 ohm in series then their equivalent resistance in parallel with 3 ohm.
Explanation:
According to the given question,
R1 = 1 ohm
R2 = 3 ohm
R3 = 5 ohm
And we are asked to find what combination of these three can give equivalent resistance as 2 ohm.
We know for series combination
- R = R1+R3
Where R is the equivalent resistance of R1 and R3 joined in series combination.
Putting the values we get,
- R = 1+5 = 6 ohm
Again, for parallel combination
- 1/R' = 1/R + 1/R2
Where R' is the equivalent resistance of R and R2 joined in parallel combination.
Putting the values we get,
- 1/R' = 1/6 + 1/3
- R' = 6×3/6+3
- R' = 18/9
- R' = 2 ohm
Thus we got 2 ohm as final equivalent resistance when 1 and 5 are in series and their equivalent resistance is parallel with 3 ohm.
Answer:
Explanation:
5ohms and 1ohms resistors inbseries and then parallel with 3 ohms
[(5+1)×3]÷[5+3+1]