how can a ball be thrown 1km long?
Answers
Answered by
0
Answer:
Explanation:
By assuming that object is being projected above the ground and expecting to travel a distance of 1KM one way.
With the above assumptions:
From Kinematics,
s = u*t + 0.5*a*t*t
a = (v-u)/t
where
u is initial velocity
a is acceleration (here acceleration due to gravity 9.8 meters per second square)
t is duration of flight.
v is final velocity (here its 0 at maximum height)
s is distance traveled
s = -0.5*u*u/a
u = (-2*a*s)^(1/2)
therefore
u = (-2*(-9.8)*1000)^0.5
u = 140 m/s
so if a body is projected 140m/s it would reach 1KM height in 14.29 seconds
Similar questions