Question

how can a ball be thrown 1km long? ​

Answer 1

Answer:

Explanation:

By assuming that object is being projected above the ground and expecting to travel a distance of 1KM one way.

With the above assumptions:

From Kinematics,

s = u*t + 0.5*a*t*t

a = (v-u)/t

where

u is initial velocity

a is acceleration (here acceleration due to gravity 9.8 meters per second square)

t is duration of flight.

v is final velocity (here its 0 at maximum height)

s is distance traveled

s = -0.5*u*u/a

u = (-2*a*s)^(1/2)

therefore

u = (-2*(-9.8)*1000)^0.5

u = 140 m/s

so if a body is projected 140m/s it would reach 1KM height in 14.29 seconds