Question

how can a call to an overloaded function be ambiguous​

Answer 1

Answer:

Answer. A call to an overloaded function can be ambiguous in one of the following two ways: *The arguments mentioned in the function where it is called do not match the arguments at the point where the function is called. *The same function is defined more than one time in the same program.......

Answer 2

Answer:

If two or more functions have the same name and function signature, the call to an overloaded function can be unclear.

Explanation:

• Function overloading ambiguity occurs when the compiler is unable to decide which of the overloaded functions should be invoked first.
• If the compiler detects an ambiguity error, the programme is not executed.
• For objects of class type, the function call operator () can be overloaded.
• You are not inventing a new way to call a function when you overload ().
• Instead, you're defining an operator function that can take any number of parameters.

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