How can entropy be used to predict spontaneity?
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We can assess the spontaneity of the process by calculating the entropy change of the universe. If ΔSuniv is positive, then the process is spontaneous. At both temperatures, ΔSsys = 22.1 J/K and qsurr = −6.00 kJ. Suniv < 0, so melting is nonspontaneous (not spontaneous) at −10.0 °C.
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Answered by
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Explanation:
We can assess the spontaneity of the process by calculating the entropy change of the universe. If ΔSuniv is positive, then the process is spontaneous. At both temperatures, ΔSsys = 22.1 J/K and qsurr = −6.00 kJ. Suniv < 0, so melting is nonspontaneous (not spontaneous) at −10.0 °C.
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