how ???? can find no. of factor
Attachments:
Answers
Answered by
1
hello there!!!!
1500 can resolved into two factors.
c) 24 is the answer
Case I
The divisors of 1500 are :-
1,2,3,4,5,6,10,12,15,20,25,30,50,60,75,100,125,150,250,300,375,500,750,1500
Case II
1500= 2² 3¹ 5³
A number that divides 1500 can't have other primes , it can't have any of the same primes to any higher power ..
It means that all divisors are of the form
2^i 3^j 5^k
i € { 0,1,2} j € { 0,1}. k € { 0,1,2,3,4}
Within these limits , however we are completely free and it means there are 3 possible values for i. , 2 for j and 4 possible values for k...
Total there are 3.2.4 = 24 , different divisors of 1500
hope it helps....
1500 can resolved into two factors.
c) 24 is the answer
Case I
The divisors of 1500 are :-
1,2,3,4,5,6,10,12,15,20,25,30,50,60,75,100,125,150,250,300,375,500,750,1500
Case II
1500= 2² 3¹ 5³
A number that divides 1500 can't have other primes , it can't have any of the same primes to any higher power ..
It means that all divisors are of the form
2^i 3^j 5^k
i € { 0,1,2} j € { 0,1}. k € { 0,1,2,3,4}
Within these limits , however we are completely free and it means there are 3 possible values for i. , 2 for j and 4 possible values for k...
Total there are 3.2.4 = 24 , different divisors of 1500
hope it helps....
Similar questions