how can i calculate edge length in nacl when radius of cation and anion are given
Answers
Answered by
0
Answer:
NaCl has simple cubic unit cell
If a is the edge length of unit cell then atomic radius
r=
2
a
Now, atomic radius, r= cationic radius (r
+
)+ anionic radius (r
−
)
⇒
2
a
=r
+
+r
−
Now, given a=564 pm, size of Cl
−
(r
−
)=101 pm
∴r
+
=
2
564
−100=282−181=101 pm
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2
Explanation:
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