How can i Calculate the thickness d of the aluminum metal (Al) shield to reduce 8.10^6 times (approx e^16 times) the intensity of the electric field E radiating outside the oscillator (frequency oscillator, f = 3 GHz).
Know the electrical parameters of aluminum:
σ = 36,6.106 Si/m;
µ = µ0 = 4π.10 -7 H/m
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