Question

How can I do this ?? Anshita 02​

Answer 1

Answer:

here is your answer hope it helps...

Step-by-step explanation:

Pythagoras triplet is of the form 2m ,m^2-1 and m^2+1

(i) here smallest number = 4

=>2m= 4

=> m= 2

therefore, m^2-1= (2)^2-1 = 4-1=3

m^2+1=(2)^2+1=4+1=5

(ii)here smallest number = 6

=>2m= 6

=> m= 3

therefore, m^2-1= (3)^2-1 = 9-1=8

m^2+1=(3)^2+1=9+1= 10

(iii) here smallest number = 12

=>2m= 12

=> m= 6

therefore, m^2-1= (6)^2-1 = 36-1=35

m^2+1=(6)^2+1=36+1=37

(iv)here smallest number = 16

=>2m= 16

=> m= 8

therefore, m^2-1= (8)^2-1 = 64-1=63

m^2+1=(8)^+1=64+1=65