how can i do this sum?
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by squaring on both the sides
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0
Answer:
x+1/x=4
x^4+1/x^4
=(x^2)^2+(1/x^2)^2
=(x^2+1/x^2)^2-2.x^2.1/x^2
=(x^2+1/x^2)^2-2
={(x+1/x)^2-2.x.1/x}^2-2
={(4)^2-2}^2-2
={16-2}^2-2
=14^2-2
=196-2
=194
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