Question

how can i find P in this.......?

Answer 1

product of roots=C/a
hence let be 1 root
other is 6m
product
6m×m=8/p
$6 {m}^{2} = \frac{8}{p}$
now sum of roots =-b/a
7m=14/p
m=2/p
put in 1
$\frac{24}{ {p}^{2} } = \frac{8}{p} \\ p = 3$