How can I find the zeroes of cubic polynomial: x³-2x²+5x-6...
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x³ –2x²+5x–6 =0
The above cubic polynomial has no simple rational roots that could be found using rational zeroes theorem.
So, this can be solved using the cubic formula or using similar techniques to solve.
I'll use the cubic formula.
The above cubic polynomial has only one real solution other non real complex.
the three solutions are :
x₁ ≈ 1.4328...
x₂,₃ ≈ 0.2836 ± 2.0266i
where, i=√(−1)
Please refer the attachment for the solution
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