how can i find the zeros of quadratic polynomial 8x^2-4
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8x^2-4=0
4(2x^2-1)=0
(squareroot(2)*x)+1)*(squareroot(2)*x)-1 =0
x = -1/squareroot(2)*x or x = 1/squareroot(2)*x
4(2x^2-1)=0
(squareroot(2)*x)+1)*(squareroot(2)*x)-1 =0
x = -1/squareroot(2)*x or x = 1/squareroot(2)*x
Answered by
7
it is right answer
I hope it helps u
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