Math, asked by ruby39137, 7 months ago

how can i prove pithogras therom????

Answers

Answered by Anonymous

Answer:

$\huge\boxed{\fcolorbox{red}{Yellow}{Answer}}$

$<font color="red">$

Proof of Pythagorean Theorem. The proof of Pythagorean Theorem in mathematics is very important. In a right angle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. States that in a right triangle that, the square of a (a2) plus the square of b (b2) is equal to the square of c (c2) ...

$<!DOCTYPE html> <html> <svg width="100%" height="300px">\ \textless \ br /\ \textgreater \ <g id="R1" transform="translate(250 250)"> \ \textless \ br /\ \textgreater \ <ellipse rx="100" ry="0" opacity=".3">\ \textless \ br /\ \textgreater \ <animateTransform attributeName="transform" type="rotate" dur="7s" from="0" to="360" repeatCount="indefinite" />\ \textless \ br /\ \textgreater \ <animate attributeName="cx" dur="8s" values="-20; 220; -20" repeatCount="indefinite" />\ \textless \ br /\ \textgreater \ <animate attributeName="ry" dur="3s" values="10; 60; 10" repeatCount="indefinite" />\ \textless \ br /\ \textgreater \ </ellipse>\ \textless \ br /\ \textgreater \ </g><use xlink:href="#R1" transform="rotate(72 390 150)" />\ \textless \ br /\ \textgreater \ <use xlink:href="#R1" transform="rotate(144 390 150)" />\ \textless \ br /\ \textgreater \ <use xlink:href="#R1" transform="rotate(216 390 150)" />\ \textless \ br /\ \textgreater \ <use xlink:href="#R1" transform="rotate(288 390 150)" />\ \textless \ br /\ \textgreater \ </svg></body></html>$

$<marquee behaviour-move> <font color ="red"><h1>❣️☺️TheSnowyPrince☺❣️</h1></marquee>$

$<marquee> <font color ="green"><h1>✌️♥️ Follow me♥️✌️</marquee>$

☺️Mark my answer as BRAINLIEST ☺️

Answered by Anonymous

Step-by-step explanation:

The formula for Pythagoras, for a right-angled triangle, is given by; c2=a2+b2

Previous Question

Next Question

how can i prove pithogras therom????​

Answers

how can i prove pithogras therom????