Question

how can i solve this inequality -2>3(b+4)/2

Answer 1

Answer:

2

Step-by-step explanation:

Answer 2

Answer:

$\bold \purple{answer} \\ \\ b < - \frac{16}{3}$

Step-by-step explanation:

$- 2 > 3(b + 4) \div 2 =$

Multiply both sides by 2 since 2 is positive , the inequality direction remain the same .

$- 2 \times 2 > 3(b + 4)$

Multiply -2 and 2 to get -4

$- 4 > 3(b + 4)$

use the distribution property to multiply 3 by b+4

$- 4 > 3b + 12$

Swap sides so that all variables terms are on the left hand side . this change the sign direction .

$3b + 12 < - 4$

Subtract 12 from both sides

$3b < - 4 - 12$

subtract 12 from -4 to get -16

$3b < - 16$

Divide both sides by 3 since 3 is positive, the inquatity direction remain the same

$b < - \frac{16}{3}$

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Hence the final answer is

$b < - \frac{16}{3}$