how can molecules of water, nitrogen dioxide, co2 and ammonia held together.
Answers
Ammonia: NH3(g)
Oxygen Gas: O2(g)
Nitrogen Monoxide: NO(g)
Water Vapor: H2O(g)
Our equation now looks like the following:
NH3(g)+O2(g)→NO(g)+H2O(g)
Luckily, we have a single-element molecule as a reactant, meaning this can be saved for last and easily balanced to fit the rest of the symbols.
The first step we should take is seeing that there are 2H on the right side and 3H on the left, meaning we need 6H on each side:
2NH3(g)+O2(g)→NO(g)+3H2O(g)
We can now balance nitrogen:
2NH3(g)+O2(g)→2NO(g)+3H2O(g)
Summing up the oxygen on both sides of the equation, we see that the right has 5 oxygens while the left has 2 : we must give the O2 a coefficient of 52 and multiply the equation by 2 because we should not generally have fractional coefficients:
4NH3(g)+5O2(g)→4NO(g)+6H2O(g)
Answer:
parts of nitric oxide and nitrogen dioxide, NO2, is cooled to −21 °C (−6 °F), the gases form dinitrogen trioxide, a blue liquid consisting of N2O3 molecules.