Math, asked by soldiersatya, 10 months ago

how can prove 2+2 is 6

Answers

Answered by shadowsabers03

Okay. See below.

Assume the equality given below.

$\boxed{\frac{5x+4}{5x+6} \ = \ \frac{5x+6}{5x+4}}$

Do cross multiplication.

$\boxed{(5x+4)(5x+4)=(5x+6)(5x+6)} \\ \\ \\ \boxed{\Rightarrow\ (5x+4)^2=(5x+6)^2}$

Take the square root of both sides.

$\boxed{5x+4=5x+6}$

Subtract 5x from both sides, and we get,

$\boxed{4=6} \\ \\ \\ \boxed{\Rightarrow\ 2+2=6}$

Hence proved!

Find yourself where I've mistaken! ;-)

Hope this helps. Plz mark it as the brainliest.

Thank you. :-))

zaidazmi8442: you taken wrong, here x is a variable so take any one value for which your question will be true

kalramanan10oct: ok

zaidazmi8442: you prove this type that suppose 4/6=6/4, square of 4=square of six. so 4=6

shadowsabers03: Actually x = -1 in my assumption. When the square root of both sides is taken, either LHS or RHS shall be negative. But I didn't take it, so that I could prove 2+2 = 6! That's all!!!

shadowsabers03: Actual method is given below.

(5x+4)^2=(5x+6)^2

5x+4 = -(5x+6)

5x+4= -5x-6

5x + 5x = -6 - 4

10x = -10

x = -1

shadowsabers03: And

-(5x + 4) = 5x + 6

- 5x - 4 = 5x + 6

5x + 5x = - 6 - 4

10x = -10

x = -1

shadowsabers03: But supposing 4/6 = 6/4, as you said, is not cool! I didn't mention that x = 0.

shadowsabers03: Such assumption can't be taken too. But my assumption and method is like,

Assume a = b

a = b

a^2 = ab

a^2 - b^2 = ab - b^2

(a + b)(a - b) = b(a - b)

a + b = b

b + b = b (Because, a = b)

2b = b

2 = 1

Here, can you say that a and b are variables?!

shadowsabers03: Here, the error occurred is, at the fifth step, where the sides are divided by a - b. Because, as a = b, therefore, a - b = 0. So how can we divide them by a - b?!

shadowsabers03: To find the value of x in such assumptions like mine:

If (ax - b) / (ax - c) = (ax - c) / (ax - b),

then x = (b + c) / 2a

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