how can
![\sqrt{2 \times 20 } = 20 \sqrt{2} \sqrt{2 \times 20 } = 20 \sqrt{2}](https://tex.z-dn.net/?f=+%5Csqrt%7B2+%5Ctimes+20+%7D++%3D+20+%5Csqrt%7B2%7D+)
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Answer:
√2×20 can be written as √40
If we simplify √40 , we get √2³ × 5
so we take out 2 and 2×5 remains under the root
∴√2×20 = 2√10
not 20√2
Hope it helped :)
Answered by
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Step-by-step explanation:
√2 × 20 = 20√2
√2 × √20 = 20√2
√2 on both the side cancel.
= √20 = 20
√20 × √20 = 20
So
1 = √20
1 = √4 × √5
1 = 2√5
Hence proved that both are not equal
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