how can the number 39 be divided into two parts in order the sum of 2÷3 of one part and 3÷4 of the other part is 28
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x + y = 39
(2x/3 + 3y/4 = 28)*12 to eliminate the fractions
8x+9y=336
(x+y=39)*8
8x+8y=312
Now solve;
8x+9y=336
- 8x+8y=312
y=24
x+y=39
x=15
Therefore, x=15 and y=24.
(2x/3 + 3y/4 = 28)*12 to eliminate the fractions
8x+9y=336
(x+y=39)*8
8x+8y=312
Now solve;
8x+9y=336
- 8x+8y=312
y=24
x+y=39
x=15
Therefore, x=15 and y=24.
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