Question

How can the number 50 be divided into two parts so that u times one past is no less than a times the other?​

Answer 1

Answer:

Step-by-step explanation:

⇒x+y=50

⇒y=50−x     I

Also sum of their reciprocals in 1/12

⇒1x+1y=112

⇒x+yxy=112

⇒xy=12(x+y)

⇒x(50−x)=600    {fromI}

⇒50x−x2=600

⇒x2−50x+600=0

⇒x2−30x−20x+600=0

⇒x(x−30)−20(x−30)=0

⇒(x−20)(x−30)=50

⇒x=20  or  x=30

When x=20

y=50−20=30

When x=30

y=50−30−20

∴The two parts of 50 are 20 and 30