How can the whole charge of a conductor be transferred to another isolated conductor?
Answers
Explanation:
You cannot transfer ALL of the charge, there will be at least some losses. You should be able to come close if you connect them via a low-resistance switch and an inductor. You must monitor the current flow when the switch is closed. The current will exponentially rise according to the resonant frequency of LC (the "L" being your inductor, and the "C" the capacitance between the 2 conductors), peak at a point where the charge transferred is 1/2 the total, then decay back toward zero. Just as it reaches zero, open the switch.
If you wait a bit longer to open the switch, you can transfer more charge, but the first conductor will begin to charge at the opposite polarity. What you've created here is a parallel resonant tank circuit.
Answer:
It is not possible to transfer all of the charge...
You cannot transfer ALL of the charge, there will be at least some losses. You should be able to come close if you connect them via a low-resistance switch and an inductor. You must monitor the current flow when the switch is closed. The current will exponentially rise according to the resonant frequency of LC (the "L" being your inductor, and the "C" the capacitance between the 2 conductors), peak at a point where the charge transferred is 1/2 the total, then decay back toward zero. Just as it reaches zero, open the switch.
If you wait a bit longer to open the switch, you can transfer more charge, but the first conductor will begin to charge at the opposite polarity. What you've created here is a parallel resonant tank circuit.
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