Question

How can three resistances of 2, 3 and 6 ohms be connected so as to give a total resistance of 1 ohm? Justify your answer?

Answer 1

$\bold{RESISTANCE}$

Resistance is the obstruction offered in the path of current.

$\bold{GIVEN,}$

Resistors with resistance 2 ohm, 3 ohm and 6 ohm when connected in circuit give net resistance as 1ohm.

▶It can only be possible if the given resistors are connected in parallel combination. Because when the resistors sre connected in parallel combination the net resistance will be less than the resistor with least resistance.

$\boxed{PROFF}$

When the resistors are connected in parallel the net resistance is

$\boxed{ \frac{1}{R_p} = \frac{1}{R_1} + \frac{1}{R_2} + n \: terms }$

$\frac{1}{R_p} = \frac{1}{2} + \frac{1}{R_3} + \frac{1}{6}$

$\frac{1}{R_p} = \frac{3 + 2 + 1}{6}$

$\frac{1}{R_p} = \frac{6}{6}$

$\huge \boxed{R_p = 1ohm}$

Hence its proved.

◼ARRANGEMENT ◼

▶A wire from positive terminal of the battery or the source is extended and then divided into three sections where resistors are connected then the unite at a point further it reaches to negative terminal hence the circuit is completed.

◼An ammeter can be connected to take the measure of current ir a voltmeter can be connected to see the measure of potential difference across the circuit.

Answer 2

Answer:

1/Rp=1/R1+1/R2+n term

1/Rp=1/2+1/R3+1/6

1/Rp=3+2+1/6

1/Rp=6/6

Rp=1 ohm

HOPE YOU LIKE THE ANSWER