how can three resistor of resistance 2 ohm 3 ohm and 6 ohm can be connected to give a total resistance of 4 ohm and 1 ohm
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Given :
Three resistor of resistance 2 Ω ,3 Ω and 6 Ω .
We have connect each in such way that we get total resistance of 4 ohm and 1 ohm .
For 4 ohm :
First 2 Ω connecting in series and other two in parallel .
1 / r [ 1 / 3 + 1 / 6 ]
1 / r = [ 1 / 2 ]
r = 2 Ω
Total Resistance = r + R
Total Resistance = 2 + 2 Ω
Total Resistance = 4 Ω .
For 1 Ω :
Connecting all resistors in parallel :
1 / R = 1 / 2 + 1 / 3 + 1 / 6 Ω
1 / R = 3 + 2 + 1 / 6 Ω
1 / R = 6 / 6 Ω
1 / R = 1 Ω
R = 1 Ω .
Hence we get answer .
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