How can three resistors of resistance 2Ω, 3Ω and 6Ω be connected to give a total resistance of (i) 11Ω (ii) 4.5Ω and (iii) 4Ω?
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When the resistances are joint in series,we will get the effective resistance of 11 Ohms by the formula:R=R1+R2+R3
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Th three resistors of resistance values of 2Ω, 3Ω and 6Ω can be combined to give the desired results using a proper combination of series and parallel connections.
To obtain (i) 11 Ω, the three resistances have to be all attached in series with each other. To obtain (ii) 4.5 Ω, the 2 Ω and 6 Ω resistances have to be connected in parallel, and their combination has to be then connected in series with the 3 Ω resistor. To obtain (ii) 4 Ω, the 3 Ω and 6 Ω resistances have to be connected in parallel, and their combination has to be then connected in series with the 2 Ω resistor.
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