Question

how can three resistors of resistance 2 ohm 3 ohm and 6 ohm be connected to give a total resistance of 1 Ohm ​

Answer 1

Given : 3 resistors of 2ohms, 3 ohms and 6ohms

To prove : resultant resistance is 1 ohms.

Solution : in order to prove, we cannot connect these resistances in series because it is sum of all resistances that is. 3 + 2 + 6 = 11 ohms which is not equal to 1 ohms

From this, we can conclude that resistances should be connected in parallel

We know that,
In parallel combination, resultant resistance is equal to

1/R = 1 /R1 + 1/R2 + 1/R3

= 1/2 + 1/3 + 1/6
= 3+ 2 + 1 /6

=1 ohms

Hence proved

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Answer 2

Referred to the attachments.....