Question

How can three resistors of resistance 2ohm 3ohm and 6ohm be conected to give a total resistance of 4ohm​

Answer 1

Answer:

Given :-

R₁ = 2 Ω

R₂ = 3 Ω

R₃ = 6 Ω

Solution :-

(a) When R2 and R3 are connected in parallel with R₁ in series we get

⇒ 1/R = 1/R₂ + 1/R₃

⇒ 1/R = 1/3 + 1/6

⇒ 1/R = 1/2

⇒ R = 2 Ω

⇒ Resistance in series = R + R₁

⇒ Resistance in series = 2 + 2 = 4 Ω

Hence, the total resistance of the circuit is 4 Ω.

(b) When R₁, R₂, R₃ are connected in parallel we get

⇒ 1/R = 1/R₁ + 1/R₂ + 1/R₃

⇒ 1/R = 1/2 + 1/3 + 1/6

⇒ 1/R = 1 Ω.

Hence, the net equivalent resistance of the circuit is 1 Ω.

Explanation:

Hope this helps