Math, asked by 12krutharth, 9 months ago

How can u solve this in elimination method 4x-3y-8=0 ;6x-3y-29÷3=0

Answers

Answered by kshitijsharma29
6

Answer:

4x-3y=8 (1)

6x-y=29/3 (2)

Multiplying the second equation with 3

18x - 3y = 29

Subtracting this equation from the first one

 

14x = 21

x = 3/2  

Hence, subsituting the value of x in equation 1

4(3/2) -3y = 8

6-8 = 3y

y = -2/3

Step-by-step explanation:

Answered by akathwal004
2

hope this answer will be helpful ♥️♥️

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