How can we connect the three capacitor each of capacitance 3 µF so that we can get (i) 9
µF (ii)4.5 µF ?
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Explanation:
We are provided with 3 capacitors each of capacitance 3 μF
We prove that the rest of the three combinations can be obtained with a combination of these.
1μF = Combining all three of them in series
2μF = Combining 2 in parallel and 1 in series with them
4.5μF = Combining 2 in series and 1 in parallel combination
Hence, only the 6 μF combination is not possible
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