Question

How can we connect the three capacitor each of capacitance 3 F so that we can get
(I) 9uF (II) 4.5uF

Answer 1

Answer:

We are provided with 3 capacitors each of capacitance 3 μF

We prove that the rest of the three combinations can be obtained with a combination of these.

1μF = Combining all three of them in series

2μF = Combining 2 in parallel and 1 in series with them

4.5μF = Combining 2 in series and 1 in parallel combination

Hence, only the 6 μF combination is not possible