Question

how can we connect three resistors of each 9 omh to get resistance of 12omh​

Answer 1

Answer:

Explanation:

Arrrrrrghhhhh @#₹@#€$€$

No possible combinations dude

Either the question is wrong or Their should an option for none of the above

See their are only four possible combinations i.e in the attachment

All three in series will give obvio 9+9+9=27Ω

All three in parallel will give 1/9+1/9+1/9=3/9=1/R so R=3Ω

Two in parallel with one in series of it

[1/9+1/9]=4.5Ω

4.5+9=13.5Ω

Now two in series with one in parallel of them

9+9=18

1/18+1/9=1+2/18=1/R

R=18/3=6Ω

Hope u get this

Thank you