How can we find the length
and breadth of a rectangle if only the perimeter is given and length is twice of breadth where perimeter is 288m ?
Answers
Answered by
176
Let the breadth (b) be x and length (l) be 2x.
Perimeter = 288m
Here,
Perimeter = 2 (l+b)
Or, 288 = 2 (2x + x)
Or, 288 = 2 (3x)
Or, 288 = 6x
Or, 288/6 = x
Or, x = 48 m
Now,
Breadth (b) = x = 48m
Length (l) = 2x = 2*48 = 96m
Hope it helps!
Perimeter = 288m
Here,
Perimeter = 2 (l+b)
Or, 288 = 2 (2x + x)
Or, 288 = 2 (3x)
Or, 288 = 6x
Or, 288/6 = x
Or, x = 48 m
Now,
Breadth (b) = x = 48m
Length (l) = 2x = 2*48 = 96m
Hope it helps!
Answered by
71
Solution :-
- Given that , length is twice of breadth and perimeter is 288m
♦ Perimeter of rectangle = 2( l + b)
Where l is length & b is breadth
And by the given information Length = 2(breadth) . So ,
=> 288 = 2 ( l + b)
=> 288 = 2 ( 2b + b )
[ Since ,Given ]
=> 288 = 2(3b)
=> 288 = 6b
=> breadth = 288/6
=> Breadth = 48m
By the given information twice of breadth equal to length , so ,
→ 2(48) = Length
→ Length = 96m
Conclusion :-
- Length = 96m
- Breadth = 48m
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