Chemistry, asked by laharipragna, 1 year ago

how can we find the n factor of given compound if the equation is not given???????? please clarify it in an understanding manner

Answers

Answered by vishagh
35
n factor is basically exchange of number of electrons if we are given a chemical equation.

But its not necessary for determining n factor.

n factor is the ioninc charge , if only a ionic compound is given.
Example:  SO²⁻ , 2 is the n factor.
                 Cl¹⁻ , 1 is the n factor.

For acid and bases.
replaceable hydrogen ion

H₂SO₄ have 2 replaceable  Hydrogen ion. Hence n factor of H2SO4 is 2.

Hope you get it. Equation is not important to determine the n factor.


abhi178: nice explanation vishagh !!!
vishagh: :)
Answered by abhi178
56
===:::::: [ n - factor ]:::;:::::===

for metal :- (1) n -factor for metals depend upon no of H-atom displaced . or no of oxidation of H-atom
example :-
MgH2 → Mg+2 + H2
hence,
n - factor of Mg = 2

similarly , for

FeH3 => 3
FeH2 =>2
CaH2=>2
AlH3 => 3 etc

(2) it's depend upon no of O-atom combined with metal. or oxidation no of O- atoms
example :-
4Al + 3O2 →2Al2O3

you see in 1 mole of Al2O3 , 3 mole of O atoms combined .
another way we can say that Al2O3 break In 2Al^+3 and 3O2^-2
hence, Oxidation state of Al = +3
so, n-factor of Al in Al2O3 = 3

similarly,
MnO2 =>4
Fe2O3 => 3 [ 2Fe^+3 & 3O^-2 ]
FeO =>Fe2O2 => 2
MgO =>Mg2O2 =>2
Na2O => 1
K2O => 1

## for elements :- for elements n- factor depends upon valency .
example :-
valency of Al = 3
so, n - factor = 3

similarly ,
Mg =>2
K =>1
Cl=> 1
Na =>1
Mn => 2 , 4 , 5 , 7 { dependds upon situation and data of question}
Fe => 2, 3
Cu => 1, 2

## for acid/ base :- depends upon acidity/ basicity .
example :-
H3BO3 is a mombasic acid so,
n - factor of H3BO3 = 1

similarly,
H2SO4 => 2
H2CO3 => 2
H3PO4 => 3
H2PO4^-1 => 2
HPO4^-2 => 1
HSO4^-1 => 1

## for salt :- for salt n-factor depnds upon total positive valancy of all metal atoms .
example :- Na2CO3 here 2 Na metal atoms present
total positive charge = +2
hence, n - factors = 2

CaCO3 , here only Ca present
total positive charge = 1 × +2 = +2
hence, n- factors = 2

similarly,
Na2SO4 => 2
CaSO4 =>2
Fe2( SO4)3 =>3
CuSO4 =>2

abhi178: ( MnO4)^-2 and Ba +2
laharipragna: so charge is n factor here
abhi178: so, n - factor of Ba = 2
abhi178: yea , this is good .charge is n- factor for compound
abhi178: i hppe know you understand
laharipragna: yes
laharipragna: reading next
abhi178: read xD
vishagh: guys i dont want to sound rude, but plzz no more comments now,so many notifs, -_-
vishagh: msg her @abhi plz _/\_
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