Science, asked by Sharon15, 1 year ago

how can we mathematically prove that weight of an object on moon is 1/6th of its weight on earth???? plz help


Deekshii1: nice question
MacTavish343: yess
Sharon15: hmm
Sharon15: plz help me
MacTavish343: i helped you!!
Sharon15: ok
Sharon15: thank u anurag36
Sharon15: sorry i typed wrong*macTavish
MacTavish343: No problem
MacTavish343: at all!

Answers

Answered by MacTavish343
2
hell...ooo


Suppose a body of mass m and its weight on the moon is Wm (where W is the weight and m is the moon;which means weight on the moon).Mass of the moon is M
and its radius is R

Weight of an object on the moon =
F with which the moon pulls.

Wm = GM*m/r2

Weight of the same object on the earth is W

Mass of the earth is 100 times of that of the moon.

Radius of the moon = R

Radius of the Earth = 4R

Weight of the object on the moon = 

We = G100M*m/(4R)2

We = G100M*m/(16R)2
Wm/We =G * M * m * 16R2/R2 * g * 100M * m 

=16/100

Wm/We = 16/100 =1/6

Weight on the moon is 1/6 weight on the earth

Sharon15: thanks
MacTavish343: welcome
Answered by niyatikansal
2
Wm = GM*m/r2

Weight of the same object on the earth is W

Mass of the earth is 100 times of that of the moon.

Radius of the moon = R

Radius of the Earth = 4R

Weight of the object on the moon = 

We = G100M*m/(4R)2

We = G100M*m/(16R)2
Wm/We =G * M * m * 16R2/R2 * g * 100M * m 

=16/100

Wm/We = 16/100 =1/6

Sharon15: thanks
niyatikansal: Welcome
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