how can we mathematically prove that weight of an object on moon is 1/6th of its weight on earth???? plz help
Deekshii1:
nice question
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hell...ooo
Suppose a body of mass m and its weight on the moon is Wm (where W is the weight and m is the moon;which means weight on the moon).Mass of the moon is M
and its radius is R
Weight of an object on the moon =
F with which the moon pulls.
Wm = GM*m/r2
Weight of the same object on the earth is W
Mass of the earth is 100 times of that of the moon.
Radius of the moon = R
Radius of the Earth = 4R
Weight of the object on the moon =
We = G100M*m/(4R)2
We = G100M*m/(16R)2
Wm/We =G * M * m * 16R2/R2 * g * 100M * m
=16/100
Wm/We = 16/100 =1/6
Weight on the moon is 1/6 weight on the earth
Suppose a body of mass m and its weight on the moon is Wm (where W is the weight and m is the moon;which means weight on the moon).Mass of the moon is M
and its radius is R
Weight of an object on the moon =
F with which the moon pulls.
Wm = GM*m/r2
Weight of the same object on the earth is W
Mass of the earth is 100 times of that of the moon.
Radius of the moon = R
Radius of the Earth = 4R
Weight of the object on the moon =
We = G100M*m/(4R)2
We = G100M*m/(16R)2
Wm/We =G * M * m * 16R2/R2 * g * 100M * m
=16/100
Wm/We = 16/100 =1/6
Weight on the moon is 1/6 weight on the earth
Answered by
2
Wm = GM*m/r2
Weight of the same object on the earth is W
Mass of the earth is 100 times of that of the moon.
Radius of the moon = R
Radius of the Earth = 4R
Weight of the object on the moon =
We = G100M*m/(4R)2
We = G100M*m/(16R)2
Wm/We =G * M * m * 16R2/R2 * g * 100M * m
=16/100
Wm/We = 16/100 =1/6
Weight of the same object on the earth is W
Mass of the earth is 100 times of that of the moon.
Radius of the moon = R
Radius of the Earth = 4R
Weight of the object on the moon =
We = G100M*m/(4R)2
We = G100M*m/(16R)2
Wm/We =G * M * m * 16R2/R2 * g * 100M * m
=16/100
Wm/We = 16/100 =1/6
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