Question

How can we pass optional or keyword parameters from one function to another in Python ?

Answer 1

Notice the syntax of the call to func2(). Since kwargs is a Python dict, we can't just pass it to func2(). We have to “unpack” it into a sequence of keyword arguments, and the ** operator does that.

Answer 2

We can pass optional or keyword parameters from one function to another in Python as follows:

• Consider a function func , which accepts keyword args -

def func (**kwargs):

   print('func kwargs:', kwargs)

• Consider another function funcy , which keywords args along with 3 other args

def funcy (a, b, c, **kwargs):

  print('other args:', a, b, c)

  print('keyword args:', kwargs)

• To pass the keywords from func() into funcy(), this should be done,

def funcy(a, b, c, **kwargs):

    print('other args:', a, b, c)

    print('keyword args:', kwargs)

    func(**kwargs)