Question

How can we prepare 0.5M HCl solution in 100 ml of water with 37% purity?

Answer 1

Explanation:

assume you want to prepare HCl 0.5 M from HCl 37% (that is, concentrated hydrochloric acid).

It is a dilution problem: HCl 37% can be assumed to be about 12 M, so it has to be diluted down to 0.5 M. Use this equation:

M1 V1 = M2 V2

M1 = initial concentration (here, 12 M)

V1 = amount of HCl 12 M you need to pick up and, subsequently, dilute

M2 = final concentration (here, 0.5 M)

V2 = amount of HCl 0.5 M you want to make

Solve for V1, you will have the amount (either in mL or L) of HCl 12 M you must use to make up the final solution till the desired volume.

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