Question

How can we prepare 1mM solution of silver nitrate in 250 ml of solution

Answer 1

Explanation:

In your case, you have

molarity

=

0.100 mol

.

L

−

1

This means that for every

1 L

=

10

3

.

mL

your solution will contain

0.100 moles

of silver nitrate,

AgNO

3

. the solute.

Now, notice that your solution has a volume of

250 mL

=

10

3

.

mL

4

This means that in order to have a molarity of

0.100 mol L

−

1

, the solution must contain

0.100 moles AgNO

3

4

=

0.025 moles AgNO

3

Finally, to convert the number of moles to grams, use the molar mass of silver nitrate

0.025

moles AgNO

3

⋅

169.87 g

1

mole AgNO

3

=

4.2 g

−−−−

The answer is rounded to two sig figs, the number of sig figs you have for the volume of the solution.